![]() ![]() Moment of inertia of the solid sphere with its diameter is given by: I = 2 M R 2/ 5 Now the density for sphere having mass M/8 and radius “r” is given by: ρ= (M/8)/4πr 3/3 Volume of a sphere having radius “R” is given by: V R= 4πR 3/3įor the sphere of mass “M” and radius “R”, the density equation will become: ρ= M/ 4πR 3/3 Now the volume of a sphere having radius “r” is given by : V r= 4πr 3/3 ![]() The bigger sphere is recast into 8 smaller spheres therefore, mass is M/8, and the supposed radius is demonstrated by “r”. Suppose that the mass and radius of the bigger sphere are demonstrated by “M” and “R”. V=4πR 3/3, where “V” shows volume and “R” is the radius. Where “ρ”, “M”, and “V” show density, mass, and volume, respectively. Moreover, the density will remain the same because both bodies have the same material. Since the sphere is recast into 8 smaller pieces hence the mass is given by: M/8 Solution: Moment of Inertia of the solid sphere is given by: Determine the moment of inertia of a smaller sphere about its diameter. Problem: A solid sphere has a moment of inertia “I” about its diameter and is recast into identical small 8 spheres. Question#2 Calculating the moment of inertia of a solid sphere Hence the moment of inertia of the hollow sphere of mass 55 kg and radius 0.120 m is 0.528 kg.m 2. Substituting the values in the above equation: Solution: The solution requires the following expression for calculation: Problem: Determine the moment of inertia of a hollow sphere of mass 55 kg. So, the moment of inertia of Hollow Sphere, I = 2/3 MR 2 Moment of Inertia of Sphere Calculation Question#1 Determining the moment of inertia of a hollow sphere Now, putting the value of DA in equation in (1), Remember, It is to create a note that, we tend to get R dθ from the equation of arc length, S = R θ
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |